Case Study Springfield Express

a) Fixed hail = 3,150,000 160x = 70x + 3,150,000 90x = 3,150,000 X = 35,000 passengers break-even Break-even revenue = 35,000x160 = 5,600,000 b) @ 70% deputation = 90x0.7 = 63 Break-even per car = 35,000 / 63 = 556 approx. c) Sale price = xcl 190x = 70x + 3,150,000 X = 26,250 break-even passengers @ 60% effect = 90x0.6 = 54 Break-even cars = 26,250 / 54 = 486 approx. d) untried variable cost = 90 per passenger 160x = 90x + 3,150,000 X = 45,000 break-even passengers @ 70% load = 90x0.7 = 63 Break-even cars = 45,000 / 63 = 714 cars e) afterward tax becharm ahead = 750,000 Then before tax get ahead: (let profit = y) y 0.3y = 750,000 y = 1,071,429 approx. 1,071,429 = Sales Cost 1,071,429 = 205x (85x + 3,600,000) 1,071,429 = 205x 85x 3,600,000 120x = 4,671,429 X = 38,929 passengers f) primitive seats occupied by 70% load = 50x90x 0.7 = 3,150 part occupied by extra load = 50x90x0.

1 = 450 Per solar day Revenue (3,150x160) + (450x120) = 558,000 inconsistent Costs per day = 70x3,600 = 252,000 Income per day = 558,000 252,000 = 306,000 Income per calendar month = 306,000x30 = 9,180,000 Profit = 9,180,000 3,150,000 180,000 = 5,850,000 g) At 60% load per car passenger = 90 x0.6 = 54 Break-even passengers for a month! 175x = 70x + 250,000 X = 2,380 passenger 1) The federation should obtain the route if there are much than 2,380 passengers on this route every month. 2) 120,000 = 175x 70x 250,000 X = 3,524 passengers At 60% load = 90x0.6 = 54 Passenger cars = 3,524 / 54 = 65 approx. 3) At 75% load = 90x0.75 = 67.5 Passenger cars = 3,524 / 67.5 = 52 approx. 4) Springfield needs to discipline couple of things first, mainly...If you want to get a full essay, mass it on our website: OrderCustomPaper.com

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